Base | Representation |
---|---|
bin | 1011000001100011010111… |
… | …0110111110011011000111 |
3 | 1120220210012022220021102221 |
4 | 2300120311312332123013 |
5 | 3042043411114010343 |
6 | 41440240550113211 |
7 | 2360510101115014 |
oct | 260306566763307 |
9 | 46823168807387 |
10 | 12121301313223 |
11 | 39536846538a3 |
12 | 143923334b807 |
13 | 69c05938187b |
14 | 2dc961aa870b |
15 | 1604822755ed |
hex | b0635dbe6c7 |
12121301313223 has 4 divisors (see below), whose sum is σ = 12122587948408. Its totient is φ = 12120014678040.
The previous prime is 12121301313221. The next prime is 12121301313263. The reversal of 12121301313223 is 32231310312121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12121301313223 - 21 = 12121301313221 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12121301313221) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 643303461 + ... + 643322302.
It is an arithmetic number, because the mean of its divisors is an integer number (3030646987102).
Almost surely, 212121301313223 is an apocalyptic number.
12121301313223 is a deficient number, since it is larger than the sum of its proper divisors (1286635185).
12121301313223 is an equidigital number, since it uses as much as digits as its factorization.
12121301313223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1286635184.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 12121301313223 its reverse (32231310312121), we get a palindrome (44352611625344).
The spelling of 12121301313223 in words is "twelve trillion, one hundred twenty-one billion, three hundred one million, three hundred thirteen thousand, two hundred twenty-three".
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