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12121311014 = 26060655507
BaseRepresentation
bin10110100100111110…
…01000011100100110
31011021202101101202222
423102133020130212
5144311023423024
65322441432342
7606243305111
oct132237103446
934252341688
1012121311014
11516018940a
12242349b6b2
1311b232a3a7
1482db99578
154ae23485e
hex2d27c8726

12121311014 has 4 divisors (see below), whose sum is σ = 18181966524. Its totient is φ = 6060655506.

The previous prime is 12121310969. The next prime is 12121311113. The reversal of 12121311014 is 41011312121.

12121311014 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 12121310983 and 12121311001.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3030327752 + ... + 3030327755.

It is an arithmetic number, because the mean of its divisors is an integer number (4545491631).

Almost surely, 212121311014 is an apocalyptic number.

12121311014 is a deficient number, since it is larger than the sum of its proper divisors (6060655510).

12121311014 is an equidigital number, since it uses as much as digits as its factorization.

12121311014 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6060655509.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 12121311014 its reverse (41011312121), we get a palindrome (53132623135).

The spelling of 12121311014 in words is "twelve billion, one hundred twenty-one million, three hundred eleven thousand, fourteen".

Divisors: 1 2 6060655507 12121311014