Base | Representation |
---|---|
bin | 1011000001100011011110… |
… | …0100011010010011011001 |
3 | 1120220210021022212202211101 |
4 | 2300120313210122103121 |
5 | 3042043440440013423 |
6 | 41440243453031401 |
7 | 2360510600010124 |
oct | 260306744322331 |
9 | 46823238782741 |
10 | 12121330001113 |
11 | 39536998684a3 |
12 | 1439240a85561 |
13 | 69c0622b7558 |
14 | 2dc9658153bb |
15 | 160484a407ad |
hex | b063791a4d9 |
12121330001113 has 2 divisors, whose sum is σ = 12121330001114. Its totient is φ = 12121330001112.
The previous prime is 12121330001071. The next prime is 12121330001129. The reversal of 12121330001113 is 31110003312121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11342326058569 + 779003942544 = 3367837^2 + 882612^2 .
It is a cyclic number.
It is not a de Polignac number, because 12121330001113 - 29 = 12121330000601 is a prime.
It is not a weakly prime, because it can be changed into another prime (12121330001153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060665000556 + 6060665000557.
It is an arithmetic number, because the mean of its divisors is an integer number (6060665000557).
Almost surely, 212121330001113 is an apocalyptic number.
It is an amenable number.
12121330001113 is a deficient number, since it is larger than the sum of its proper divisors (1).
12121330001113 is an equidigital number, since it uses as much as digits as its factorization.
12121330001113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 12121330001113 its reverse (31110003312121), we get a palindrome (43231333313234).
The spelling of 12121330001113 in words is "twelve trillion, one hundred twenty-one billion, three hundred thirty million, one thousand, one hundred thirteen".
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