Base | Representation |
---|---|
bin | 1011000001100011011110… |
… | …1100011101001100110101 |
3 | 1120220210021110211220212020 |
4 | 2300120313230131030311 |
5 | 3042043442010011013 |
6 | 41440244010143353 |
7 | 2360510623642641 |
oct | 260306754351465 |
9 | 46823243756766 |
10 | 12121332110133 |
11 | 395369aa78a94 |
12 | 1439241721b59 |
13 | 69c0628754ac |
14 | 2dc965c03c21 |
15 | 160484d0a623 |
hex | b0637b1d335 |
12121332110133 has 16 divisors (see below), whose sum is σ = 16864589639040. Its totient is φ = 7729486642944.
The previous prime is 12121332110093. The next prime is 12121332110159. The reversal of 12121332110133 is 33101123312121.
It is not a de Polignac number, because 12121332110133 - 213 = 12121332101941 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12121332110183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9682233 + ... + 10862241.
It is an arithmetic number, because the mean of its divisors is an integer number (1054036852440).
Almost surely, 212121332110133 is an apocalyptic number.
It is an amenable number.
12121332110133 is a deficient number, since it is larger than the sum of its proper divisors (4743257528907).
12121332110133 is a wasteful number, since it uses less digits than its factorization.
12121332110133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1328908.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 12121332110133 its reverse (33101123312121), we get a palindrome (45222455422254).
The spelling of 12121332110133 in words is "twelve trillion, one hundred twenty-one billion, three hundred thirty-two million, one hundred ten thousand, one hundred thirty-three".
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