Base | Representation |
---|---|
bin | 10001101000111100101… |
… | …101100000101001011001 |
3 | 11021212220020220211021022 |
4 | 101220330231200221121 |
5 | 124330041012400013 |
6 | 2324513210452225 |
7 | 153402300246551 |
oct | 21507455405131 |
9 | 4255806824238 |
10 | 1212199340633 |
11 | 4280aaa20296 |
12 | 176b23134075 |
13 | 8a404b35668 |
14 | 429567d6161 |
15 | 217eabd5008 |
hex | 11a3cb60a59 |
1212199340633 has 2 divisors, whose sum is σ = 1212199340634. Its totient is φ = 1212199340632.
The previous prime is 1212199340603. The next prime is 1212199340659. The reversal of 1212199340633 is 3360439912121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1160474026009 + 51725314624 = 1077253^2 + 227432^2 .
It is a cyclic number.
It is not a de Polignac number, because 1212199340633 - 220 = 1212198292057 is a prime.
It is not a weakly prime, because it can be changed into another prime (1212199340603) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606099670316 + 606099670317.
It is an arithmetic number, because the mean of its divisors is an integer number (606099670317).
Almost surely, 21212199340633 is an apocalyptic number.
It is an amenable number.
1212199340633 is a deficient number, since it is larger than the sum of its proper divisors (1).
1212199340633 is an equidigital number, since it uses as much as digits as its factorization.
1212199340633 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 209952, while the sum is 44.
The spelling of 1212199340633 in words is "one trillion, two hundred twelve billion, one hundred ninety-nine million, three hundred forty thousand, six hundred thirty-three".
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