Base | Representation |
---|---|
bin | 11011100011111110111011… |
… | …000010111111110110100011 |
3 | 120220012112000020020112002111 |
4 | 123203332323002333312203 |
5 | 111342032030012321402 |
6 | 1105451411013300151 |
7 | 34350566415124501 |
oct | 3343767302776643 |
9 | 526175006215074 |
10 | 121220000120227 |
11 | 35696127961688 |
12 | 117192b8934657 |
13 | 5283cc6431c38 |
14 | 21d11178b1671 |
15 | e033250d29d7 |
hex | 6e3fbb0bfda3 |
121220000120227 has 2 divisors, whose sum is σ = 121220000120228. Its totient is φ = 121220000120226.
The previous prime is 121220000120143. The next prime is 121220000120243. The reversal of 121220000120227 is 722021000022121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121220000120227 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 121220000120198 and 121220000120207.
It is not a weakly prime, because it can be changed into another prime (121220000120287) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60610000060113 + 60610000060114.
It is an arithmetic number, because the mean of its divisors is an integer number (60610000060114).
Almost surely, 2121220000120227 is an apocalyptic number.
121220000120227 is a deficient number, since it is larger than the sum of its proper divisors (1).
121220000120227 is an equidigital number, since it uses as much as digits as its factorization.
121220000120227 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 448, while the sum is 22.
Adding to 121220000120227 its reverse (722021000022121), we get a palindrome (843241000142348).
The spelling of 121220000120227 in words is "one hundred twenty-one trillion, two hundred twenty billion, one hundred twenty thousand, two hundred twenty-seven".
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