Base | Representation |
---|---|
bin | 1011000001100110010110… |
… | …0101011001010010010011 |
3 | 1120220212021010112221100011 |
4 | 2300121211211121102103 |
5 | 3042102031103323102 |
6 | 41440452231535351 |
7 | 2360535662665651 |
oct | 260314545312223 |
9 | 46825233487304 |
10 | 12122102011027 |
11 | 3953a55620a18 |
12 | 143941752a557 |
13 | 69c15621a258 |
14 | 2dc9da175dd1 |
15 | 1604cc6d92d7 |
hex | b0665959493 |
12122102011027 has 2 divisors, whose sum is σ = 12122102011028. Its totient is φ = 12122102011026.
The previous prime is 12122102010959. The next prime is 12122102011037. The reversal of 12122102011027 is 72011020122121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12122102011027 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12122102010989 and 12122102011007.
It is not a weakly prime, because it can be changed into another prime (12122102011037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6061051005513 + 6061051005514.
It is an arithmetic number, because the mean of its divisors is an integer number (6061051005514).
Almost surely, 212122102011027 is an apocalyptic number.
12122102011027 is a deficient number, since it is larger than the sum of its proper divisors (1).
12122102011027 is an equidigital number, since it uses as much as digits as its factorization.
12122102011027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 22.
Adding to 12122102011027 its reverse (72011020122121), we get a palindrome (84133122133148).
The spelling of 12122102011027 in words is "twelve trillion, one hundred twenty-two billion, one hundred two million, eleven thousand, twenty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •