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1212212002153 is a prime number
BaseRepresentation
bin10001101000111101011…
…101110011110101101001
311021212221010202002121111
4101220331131303311221
5124330102233032103
62324514342110321
7153402513002605
oct21507535636551
94255833662544
101212212002153
11428107089059
12176b2741b3a1
138a407649799
1442958370505
15217ebd8686d
hex11a3d773d69

1212212002153 has 2 divisors, whose sum is σ = 1212212002154. Its totient is φ = 1212212002152.

The previous prime is 1212212002121. The next prime is 1212212002159. The reversal of 1212212002153 is 3512002122121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1181377695744 + 30834306409 = 1086912^2 + 175597^2 .

It is a cyclic number.

It is not a de Polignac number, because 1212212002153 - 25 = 1212212002121 is a prime.

It is not a weakly prime, because it can be changed into another prime (1212212002159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606106001076 + 606106001077.

It is an arithmetic number, because the mean of its divisors is an integer number (606106001077).

Almost surely, 21212212002153 is an apocalyptic number.

It is an amenable number.

1212212002153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1212212002153 is an equidigital number, since it uses as much as digits as its factorization.

1212212002153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 480, while the sum is 22.

Adding to 1212212002153 its reverse (3512002122121), we get a palindrome (4724214124274).

The spelling of 1212212002153 in words is "one trillion, two hundred twelve billion, two hundred twelve million, two thousand, one hundred fifty-three".