Base | Representation |
---|---|
bin | 1011000001100110101110… |
… | …0011001101000011101011 |
3 | 1120220212112002212222112012 |
4 | 2300121223203031003223 |
5 | 3042102232214144242 |
6 | 41440510205110135 |
7 | 2360541316511252 |
oct | 260315343150353 |
9 | 46825462788465 |
10 | 12122202099947 |
11 | 3953aa7073235 |
12 | 1439444b5834b |
13 | 69c170b92374 |
14 | 2dca0958b799 |
15 | 1604d63aa282 |
hex | b066b8cd0eb |
12122202099947 has 2 divisors, whose sum is σ = 12122202099948. Its totient is φ = 12122202099946.
The previous prime is 12122202099923. The next prime is 12122202100003. The reversal of 12122202099947 is 74999020222121.
12122202099947 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12122202099947 - 26 = 12122202099883 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12122202099895 and 12122202099904.
It is not a weakly prime, because it can be changed into another prime (12122202099647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6061101049973 + 6061101049974.
It is an arithmetic number, because the mean of its divisors is an integer number (6061101049974).
Almost surely, 212122202099947 is an apocalyptic number.
12122202099947 is a deficient number, since it is larger than the sum of its proper divisors (1).
12122202099947 is an equidigital number, since it uses as much as digits as its factorization.
12122202099947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 653184, while the sum is 50.
The spelling of 12122202099947 in words is "twelve trillion, one hundred twenty-two billion, two hundred two million, ninety-nine thousand, nine hundred forty-seven".
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