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12122202099947 is a prime number
BaseRepresentation
bin1011000001100110101110…
…0011001101000011101011
31120220212112002212222112012
42300121223203031003223
53042102232214144242
641440510205110135
72360541316511252
oct260315343150353
946825462788465
1012122202099947
113953aa7073235
121439444b5834b
1369c170b92374
142dca0958b799
151604d63aa282
hexb066b8cd0eb

12122202099947 has 2 divisors, whose sum is σ = 12122202099948. Its totient is φ = 12122202099946.

The previous prime is 12122202099923. The next prime is 12122202100003. The reversal of 12122202099947 is 74999020222121.

12122202099947 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12122202099947 - 26 = 12122202099883 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12122202099895 and 12122202099904.

It is not a weakly prime, because it can be changed into another prime (12122202099647) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6061101049973 + 6061101049974.

It is an arithmetic number, because the mean of its divisors is an integer number (6061101049974).

Almost surely, 212122202099947 is an apocalyptic number.

12122202099947 is a deficient number, since it is larger than the sum of its proper divisors (1).

12122202099947 is an equidigital number, since it uses as much as digits as its factorization.

12122202099947 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 653184, while the sum is 50.

The spelling of 12122202099947 in words is "twelve trillion, one hundred twenty-two billion, two hundred two million, ninety-nine thousand, nine hundred forty-seven".