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12122203032073 is a prime number
BaseRepresentation
bin1011000001100110101110…
…0110110000101000001001
31120220212112011122100011101
42300121223212300220021
53042102232434011243
641440510241101401
72360541330442651
oct260315346605011
946825464570141
1012122203032073
113953aa764a592
121439445327861
1369c17112a714
142dca09751361
151604d64e154d
hexb066b9b0a09

12122203032073 has 2 divisors, whose sum is σ = 12122203032074. Its totient is φ = 12122203032072.

The previous prime is 12122203032059. The next prime is 12122203032127. The reversal of 12122203032073 is 37023030222121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9963031406329 + 2159171625744 = 3156427^2 + 1469412^2 .

It is an emirp because it is prime and its reverse (37023030222121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12122203032073 - 213 = 12122203023881 is a prime.

It is not a weakly prime, because it can be changed into another prime (12122203042073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6061101516036 + 6061101516037.

It is an arithmetic number, because the mean of its divisors is an integer number (6061101516037).

Almost surely, 212122203032073 is an apocalyptic number.

It is an amenable number.

12122203032073 is a deficient number, since it is larger than the sum of its proper divisors (1).

12122203032073 is an equidigital number, since it uses as much as digits as its factorization.

12122203032073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 28.

Adding to 12122203032073 its reverse (37023030222121), we get a palindrome (49145233254194).

The spelling of 12122203032073 in words is "twelve trillion, one hundred twenty-two billion, two hundred three million, thirty-two thousand, seventy-three".