Base | Representation |
---|---|
bin | 11011100100000010000010… |
… | …010111110011011000010001 |
3 | 120220012211122021210102012202 |
4 | 123210002002113303120101 |
5 | 111342110402111141040 |
6 | 1105453122513332545 |
7 | 34351045322514320 |
oct | 3344020227633021 |
9 | 526184567712182 |
10 | 121223344240145 |
11 | 356975935a0454 |
12 | 11719a90867155 |
13 | 528440a1c1114 |
14 | 21d1353a940b7 |
15 | e0346d99d015 |
hex | 6e40825f3611 |
121223344240145 has 32 divisors (see below), whose sum is σ = 171092979552768. Its totient is φ = 80711894389248.
The previous prime is 121223344240111. The next prime is 121223344240177. The reversal of 121223344240145 is 541042443322121.
It is a cyclic number.
It is not a de Polignac number, because 121223344240145 - 210 = 121223344239121 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 121223344240099 and 121223344240108.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 95476892 + ... + 96738221.
It is an arithmetic number, because the mean of its divisors is an integer number (5346655611024).
Almost surely, 2121223344240145 is an apocalyptic number.
It is an amenable number.
121223344240145 is a deficient number, since it is larger than the sum of its proper divisors (49869635312623).
121223344240145 is a wasteful number, since it uses less digits than its factorization.
121223344240145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 192215649.
The product of its (nonzero) digits is 184320, while the sum is 38.
Adding to 121223344240145 its reverse (541042443322121), we get a palindrome (662265787562266).
The spelling of 121223344240145 in words is "one hundred twenty-one trillion, two hundred twenty-three billion, three hundred forty-four million, two hundred forty thousand, one hundred forty-five".
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