Base | Representation |
---|---|
bin | 10110100101000110… |
… | …10101100001010111 |
3 | 1011021211110101121120 |
4 | 23102203111201113 |
5 | 144311314210033 |
6 | 5322521215023 |
7 | 606255545241 |
oct | 132243254127 |
9 | 34254411546 |
10 | 12122413143 |
11 | 5160871465 |
12 | 2423931473 |
13 | 11b2624c39 |
14 | 82dda5091 |
15 | 4ae3a11b3 |
hex | 2d28d5857 |
12122413143 has 8 divisors (see below), whose sum is σ = 16865966208. Its totient is φ = 7730234424.
The previous prime is 12122413141. The next prime is 12122413169. The reversal of 12122413143 is 34131422121.
12122413143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12122413143 - 21 = 12122413141 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12122413141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 87843505 + ... + 87843642.
It is an arithmetic number, because the mean of its divisors is an integer number (2108245776).
Almost surely, 212122413143 is an apocalyptic number.
12122413143 is a deficient number, since it is larger than the sum of its proper divisors (4743553065).
12122413143 is a wasteful number, since it uses less digits than its factorization.
12122413143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 175687173.
The product of its digits is 1152, while the sum is 24.
Adding to 12122413143 its reverse (34131422121), we get a palindrome (46253835264).
The spelling of 12122413143 in words is "twelve billion, one hundred twenty-two million, four hundred thirteen thousand, one hundred forty-three".
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