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12123004457 is a prime number
BaseRepresentation
bin10110100101001011…
…00101111000101001
31011021212120102202002
423102211211320221
5144311442120312
65322542020345
7606263560214
oct132245457051
934255512662
1012123004457
115161135753
122423b776b5
1311b27a1125
148300ba77b
154ae46b4c2
hex2d2965e29

12123004457 has 2 divisors, whose sum is σ = 12123004458. Its totient is φ = 12123004456.

The previous prime is 12123004403. The next prime is 12123004463. The reversal of 12123004457 is 75440032121.

12123004457 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9514246681 + 2608757776 = 97541^2 + 51076^2 .

It is an emirp because it is prime and its reverse (75440032121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12123004457 - 26 = 12123004393 is a prime.

It is not a weakly prime, because it can be changed into another prime (12123004477) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6061502228 + 6061502229.

It is an arithmetic number, because the mean of its divisors is an integer number (6061502229).

Almost surely, 212123004457 is an apocalyptic number.

It is an amenable number.

12123004457 is a deficient number, since it is larger than the sum of its proper divisors (1).

12123004457 is an equidigital number, since it uses as much as digits as its factorization.

12123004457 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6720, while the sum is 29.

Adding to 12123004457 its reverse (75440032121), we get a palindrome (87563036578).

The spelling of 12123004457 in words is "twelve billion, one hundred twenty-three million, four thousand, four hundred fifty-seven".