Base | Representation |
---|---|
bin | 1011000001101001101110… |
… | …1101001011001010001001 |
3 | 1120220221121102010120110021 |
4 | 2300122123231023022021 |
5 | 3042110411031114402 |
6 | 41441122305420441 |
7 | 2360600326642243 |
oct | 260323355131211 |
9 | 46827542116407 |
10 | 12123010019977 |
11 | 395438112353a |
12 | 143962b63a721 |
13 | 69c26c38915c |
14 | 2dca849b9093 |
15 | 160532298d37 |
hex | b069bb4b289 |
12123010019977 has 2 divisors, whose sum is σ = 12123010019978. Its totient is φ = 12123010019976.
The previous prime is 12123010019873. The next prime is 12123010020083. The reversal of 12123010019977 is 77991001032121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12053527168761 + 69482851216 = 3471819^2 + 263596^2 .
It is a cyclic number.
It is not a de Polignac number, because 12123010019977 - 27 = 12123010019849 is a prime.
It is not a weakly prime, because it can be changed into another prime (12123010019177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6061505009988 + 6061505009989.
It is an arithmetic number, because the mean of its divisors is an integer number (6061505009989).
Almost surely, 212123010019977 is an apocalyptic number.
It is an amenable number.
12123010019977 is a deficient number, since it is larger than the sum of its proper divisors (1).
12123010019977 is an equidigital number, since it uses as much as digits as its factorization.
12123010019977 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 47628, while the sum is 43.
The spelling of 12123010019977 in words is "twelve trillion, one hundred twenty-three billion, ten million, nineteen thousand, nine hundred seventy-seven".
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