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12123010019977 is a prime number
BaseRepresentation
bin1011000001101001101110…
…1101001011001010001001
31120220221121102010120110021
42300122123231023022021
53042110411031114402
641441122305420441
72360600326642243
oct260323355131211
946827542116407
1012123010019977
11395438112353a
12143962b63a721
1369c26c38915c
142dca849b9093
15160532298d37
hexb069bb4b289

12123010019977 has 2 divisors, whose sum is σ = 12123010019978. Its totient is φ = 12123010019976.

The previous prime is 12123010019873. The next prime is 12123010020083. The reversal of 12123010019977 is 77991001032121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12053527168761 + 69482851216 = 3471819^2 + 263596^2 .

It is a cyclic number.

It is not a de Polignac number, because 12123010019977 - 27 = 12123010019849 is a prime.

It is not a weakly prime, because it can be changed into another prime (12123010019177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6061505009988 + 6061505009989.

It is an arithmetic number, because the mean of its divisors is an integer number (6061505009989).

Almost surely, 212123010019977 is an apocalyptic number.

It is an amenable number.

12123010019977 is a deficient number, since it is larger than the sum of its proper divisors (1).

12123010019977 is an equidigital number, since it uses as much as digits as its factorization.

12123010019977 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 47628, while the sum is 43.

The spelling of 12123010019977 in words is "twelve trillion, one hundred twenty-three billion, ten million, nineteen thousand, nine hundred seventy-seven".