Base | Representation |
---|---|
bin | 10001101001000010110… |
… | …010011111100010110011 |
3 | 11021220011100210102010101 |
4 | 101221002302133202303 |
5 | 124330243113411011 |
6 | 2324531252213231 |
7 | 153404646053662 |
oct | 21510262374263 |
9 | 4256140712111 |
10 | 1212301310131 |
11 | 4281525374aa |
12 | 176b5130a217 |
13 | 8a41ccb8742 |
14 | 4296617add9 |
15 | 21804b282c1 |
hex | 11a42c9f8b3 |
1212301310131 has 2 divisors, whose sum is σ = 1212301310132. Its totient is φ = 1212301310130.
The previous prime is 1212301310111. The next prime is 1212301310149. The reversal of 1212301310131 is 1310131032121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1212301310131 - 211 = 1212301308083 is a prime.
It is a super-2 number, since 2×12123013101312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1212301310099 and 1212301310108.
It is not a weakly prime, because it can be changed into another prime (1212301310111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606150655065 + 606150655066.
It is an arithmetic number, because the mean of its divisors is an integer number (606150655066).
Almost surely, 21212301310131 is an apocalyptic number.
1212301310131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1212301310131 is an equidigital number, since it uses as much as digits as its factorization.
1212301310131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 1212301310131 its reverse (1310131032121), we get a palindrome (2522432342252).
The spelling of 1212301310131 in words is "one trillion, two hundred twelve billion, three hundred one million, three hundred ten thousand, one hundred thirty-one".
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