Base | Representation |
---|---|
bin | 1011000001101001110001… |
… | …0011000001110011000011 |
3 | 1120220221122002210201102121 |
4 | 2300122130103001303003 |
5 | 3042110421101134412 |
6 | 41441123302225111 |
7 | 2360600510201533 |
oct | 260323423016303 |
9 | 46827562721377 |
10 | 12123019943107 |
11 | 3954386790977 |
12 | 1439632a25197 |
13 | 69c271451a28 |
14 | 2dca8603d4c3 |
15 | 1605330a9107 |
hex | b069c4c1cc3 |
12123019943107 has 2 divisors, whose sum is σ = 12123019943108. Its totient is φ = 12123019943106.
The previous prime is 12123019943059. The next prime is 12123019943197. The reversal of 12123019943107 is 70134991032121.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12123019943107 is a prime.
It is a super-2 number, since 2×121230199431072 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12123019943197) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6061509971553 + 6061509971554.
It is an arithmetic number, because the mean of its divisors is an integer number (6061509971554).
Almost surely, 212123019943107 is an apocalyptic number.
12123019943107 is a deficient number, since it is larger than the sum of its proper divisors (1).
12123019943107 is an equidigital number, since it uses as much as digits as its factorization.
12123019943107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81648, while the sum is 43.
The spelling of 12123019943107 in words is "twelve trillion, one hundred twenty-three billion, nineteen million, nine hundred forty-three thousand, one hundred seven".
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