Base | Representation |
---|---|
bin | 1011000001101010000010… |
… | …1101101101000000011001 |
3 | 1120220221211021020110200221 |
4 | 2300122200231231000121 |
5 | 3042111044033412242 |
6 | 41441134510400041 |
7 | 2360602400100256 |
oct | 260324055550031 |
9 | 46827737213627 |
10 | 12123094044697 |
11 | 39544145a3559 |
12 | 1439653800021 |
13 | 69c2838c841c |
14 | 2dca91c0c42d |
15 | 160539845167 |
hex | b06a0b6d019 |
12123094044697 has 2 divisors, whose sum is σ = 12123094044698. Its totient is φ = 12123094044696.
The previous prime is 12123094044667. The next prime is 12123094044707. The reversal of 12123094044697 is 79644049032121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9073656087001 + 3049437957696 = 3012251^2 + 1746264^2 .
It is a cyclic number.
It is not a de Polignac number, because 12123094044697 - 219 = 12123093520409 is a prime.
It is a super-3 number, since 3×121230940446973 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (12123094044617) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6061547022348 + 6061547022349.
It is an arithmetic number, because the mean of its divisors is an integer number (6061547022349).
Almost surely, 212123094044697 is an apocalyptic number.
It is an amenable number.
12123094044697 is a deficient number, since it is larger than the sum of its proper divisors (1).
12123094044697 is an equidigital number, since it uses as much as digits as its factorization.
12123094044697 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2612736, while the sum is 52.
The spelling of 12123094044697 in words is "twelve trillion, one hundred twenty-three billion, ninety-four million, forty-four thousand, six hundred ninety-seven".
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