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121241114121233 is a prime number
BaseRepresentation
bin11011100100010010100101…
…100010100001010000010001
3120220021112111200221220102202
4123210102211202201100101
5111342403300203334413
61105505222055452545
734352244555146651
oct3344224542412021
9526245450856382
10121241114121233
11356a4082199097
121172140b987155
135285cac850262
1421d215badc361
15e03b5da4ce58
hex6e44a58a1411

121241114121233 has 2 divisors, whose sum is σ = 121241114121234. Its totient is φ = 121241114121232.

The previous prime is 121241114121187. The next prime is 121241114121313. The reversal of 121241114121233 is 332121411142121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 118842527826064 + 2398586295169 = 10901492^2 + 1548737^2 .

It is a cyclic number.

It is not a de Polignac number, because 121241114121233 - 210 = 121241114120209 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 121241114121196 and 121241114121205.

It is not a weakly prime, because it can be changed into another prime (121241114124233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60620557060616 + 60620557060617.

It is an arithmetic number, because the mean of its divisors is an integer number (60620557060617).

Almost surely, 2121241114121233 is an apocalyptic number.

It is an amenable number.

121241114121233 is a deficient number, since it is larger than the sum of its proper divisors (1).

121241114121233 is an equidigital number, since it uses as much as digits as its factorization.

121241114121233 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2304, while the sum is 29.

Adding to 121241114121233 its reverse (332121411142121), we get a palindrome (453362525263354).

The spelling of 121241114121233 in words is "one hundred twenty-one trillion, two hundred forty-one billion, one hundred fourteen million, one hundred twenty-one thousand, two hundred thirty-three".