Base | Representation |
---|---|
bin | 10001101001001111010… |
… | …011001101001000001001 |
3 | 11021220200222202112102012 |
4 | 101221033103031020021 |
5 | 124331210332241131 |
6 | 2325004151145305 |
7 | 153413105151623 |
oct | 21511723151011 |
9 | 4256628675365 |
10 | 1212511212041 |
11 | 42824aa72958 |
12 | 176bab675235 |
13 | 8a45462ba5c |
14 | 42985db9c13 |
15 | 2181828b52b |
hex | 11a4f4cd209 |
1212511212041 has 2 divisors, whose sum is σ = 1212511212042. Its totient is φ = 1212511212040.
The previous prime is 1212511212013. The next prime is 1212511212061. The reversal of 1212511212041 is 1402121152121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1211925765625 + 585446416 = 1100875^2 + 24196^2 .
It is a cyclic number.
It is not a de Polignac number, because 1212511212041 - 222 = 1212507017737 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1212511211998 and 1212511212016.
It is not a weakly prime, because it can be changed into another prime (1212511212061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606255606020 + 606255606021.
It is an arithmetic number, because the mean of its divisors is an integer number (606255606021).
Almost surely, 21212511212041 is an apocalyptic number.
It is an amenable number.
1212511212041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1212511212041 is an equidigital number, since it uses as much as digits as its factorization.
1212511212041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 320, while the sum is 23.
Adding to 1212511212041 its reverse (1402121152121), we get a palindrome (2614632364162).
The spelling of 1212511212041 in words is "one trillion, two hundred twelve billion, five hundred eleven million, two hundred twelve thousand, forty-one".
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