Base | Representation |
---|---|
bin | 11011100100011100001011… |
… | …001110010101100100110111 |
3 | 120220022112002020112211100210 |
4 | 123210130023032111210313 |
5 | 111343040341432304033 |
6 | 1105514043453040503 |
7 | 34353060655056114 |
oct | 3344341316254467 |
9 | 526275066484323 |
10 | 121251410041143 |
11 | 356a8485a50108 |
12 | 11723403a86133 |
13 | 5286c6093a365 |
14 | 21d285729190b |
15 | e040628b0d63 |
hex | 6e470b395937 |
121251410041143 has 16 divisors (see below), whose sum is σ = 167267524608000. Its totient is φ = 78035591098080.
The previous prime is 121251410041127. The next prime is 121251410041187. The reversal of 121251410041143 is 341140014152121.
It is not a de Polignac number, because 121251410041143 - 24 = 121251410041127 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 121251410041143.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121251410041943) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 100230343 + ... + 101432856.
It is an arithmetic number, because the mean of its divisors is an integer number (10454220288000).
Almost surely, 2121251410041143 is an apocalyptic number.
121251410041143 is a deficient number, since it is larger than the sum of its proper divisors (46016114566857).
121251410041143 is a wasteful number, since it uses less digits than its factorization.
121251410041143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 201670142.
The product of its (nonzero) digits is 3840, while the sum is 30.
Adding to 121251410041143 its reverse (341140014152121), we get a palindrome (462391424193264).
The spelling of 121251410041143 in words is "one hundred twenty-one trillion, two hundred fifty-one billion, four hundred ten million, forty-one thousand, one hundred forty-three".
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