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121253221054193 is a prime number
BaseRepresentation
bin11011100100011101110111…
…001010110011011011110001
3120220022200202110021211020012
4123210131313022303123301
5111343103044042213233
61105514543305224305
734353153565322414
oct3344356712633361
9526280673254205
10121253221054193
11356a9225247008
121172382a492095
13528718bbb5107
1421d29899d3b7b
15e0411b892548
hex6e47772b36f1

121253221054193 has 2 divisors, whose sum is σ = 121253221054194. Its totient is φ = 121253221054192.

The previous prime is 121253221054177. The next prime is 121253221054243. The reversal of 121253221054193 is 391450122352121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 90595217495104 + 30658003559089 = 9518152^2 + 5536967^2 .

It is a cyclic number.

It is not a de Polignac number, because 121253221054193 - 24 = 121253221054177 is a prime.

It is a super-2 number, since 2×1212532210541932 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 121253221054193.

It is not a weakly prime, because it can be changed into another prime (121253221054793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60626610527096 + 60626610527097.

It is an arithmetic number, because the mean of its divisors is an integer number (60626610527097).

Almost surely, 2121253221054193 is an apocalyptic number.

It is an amenable number.

121253221054193 is a deficient number, since it is larger than the sum of its proper divisors (1).

121253221054193 is an equidigital number, since it uses as much as digits as its factorization.

121253221054193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 129600, while the sum is 41.

The spelling of 121253221054193 in words is "one hundred twenty-one trillion, two hundred fifty-three billion, two hundred twenty-one million, fifty-four thousand, one hundred ninety-three".