Base | Representation |
---|---|
bin | 111000011101101011… |
… | …1100011001010010001 |
3 | 102120222110212222100111 |
4 | 1300323113203022101 |
5 | 3441312302111421 |
6 | 131412005521321 |
7 | 11521546313014 |
oct | 1607327431221 |
9 | 376873788314 |
10 | 121255113361 |
11 | 47473394398 |
12 | 1b600113241 |
13 | b5852374b5 |
14 | 5c23d0137b |
15 | 324a27aee1 |
hex | 1c3b5e3291 |
121255113361 has 2 divisors, whose sum is σ = 121255113362. Its totient is φ = 121255113360.
The previous prime is 121255113313. The next prime is 121255113383. The reversal of 121255113361 is 163311552121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 103391187025 + 17863926336 = 321545^2 + 133656^2 .
It is a cyclic number.
It is not a de Polignac number, because 121255113361 - 219 = 121254589073 is a prime.
It is not a weakly prime, because it can be changed into another prime (121255113961) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60627556680 + 60627556681.
It is an arithmetic number, because the mean of its divisors is an integer number (60627556681).
Almost surely, 2121255113361 is an apocalyptic number.
It is an amenable number.
121255113361 is a deficient number, since it is larger than the sum of its proper divisors (1).
121255113361 is an equidigital number, since it uses as much as digits as its factorization.
121255113361 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5400, while the sum is 31.
Adding to 121255113361 its reverse (163311552121), we get a palindrome (284566665482).
The spelling of 121255113361 in words is "one hundred twenty-one billion, two hundred fifty-five million, one hundred thirteen thousand, three hundred sixty-one".
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