12127433 has 2 divisors, whose sum is σ = 12127434. Its totient is φ = 12127432.

The previous prime is 12127411. The next prime is 12127447. The reversal of 12127433 is 33472121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11648569 + 478864 = 3413^2 + 692^2 .

It is a cyclic number.

It is not a de Polignac number, because 12127433 - 2⁸ = 12127177 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12127399 and 12127408.

It is not a weakly prime, because it can be changed into another prime (12127403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6063716 + 6063717.

It is an arithmetic number, because the mean of its divisors is an integer number (6063717).

Almost surely, 2^12127433 is an apocalyptic number.

It is an amenable number.

12127433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12127433 is an equidigital number, since it uses as much as digits as its factorization.

12127433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1008, while the sum is 23.

The square root of 12127433 is about 3482.4464102122. The cubic root of 12127433 is about 229.7504097782.

Adding to 12127433 its reverse (33472121), we get a palindrome (45599554).

The spelling of 12127433 in words is "twelve million, one hundred twenty-seven thousand, four hundred thirty-three".