Base | Representation |
---|---|
bin | 1011000010000011010000… |
… | …0100110111011000001001 |
3 | 1120221121021220002102011101 |
4 | 2300200310010313120021 |
5 | 3042213424000201122 |
6 | 41444214213101401 |
7 | 2361232162105252 |
oct | 260406404673011 |
9 | 46847256072141 |
10 | 12129861334537 |
11 | 3957277553581 |
12 | 143aa22027861 |
13 | 69cac193363b |
14 | 2dd1348adb29 |
15 | 1607d39e3027 |
hex | b0834137609 |
12129861334537 has 2 divisors, whose sum is σ = 12129861334538. Its totient is φ = 12129861334536.
The previous prime is 12129861334501. The next prime is 12129861334583. The reversal of 12129861334537 is 73543316892121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9114970848201 + 3014890486336 = 3019101^2 + 1736344^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12129861334537 is a prime.
It is not a weakly prime, because it can be changed into another prime (12129861304537) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6064930667268 + 6064930667269.
It is an arithmetic number, because the mean of its divisors is an integer number (6064930667269).
Almost surely, 212129861334537 is an apocalyptic number.
It is an amenable number.
12129861334537 is a deficient number, since it is larger than the sum of its proper divisors (1).
12129861334537 is an equidigital number, since it uses as much as digits as its factorization.
12129861334537 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6531840, while the sum is 55.
The spelling of 12129861334537 in words is "twelve trillion, one hundred twenty-nine billion, eight hundred sixty-one million, three hundred thirty-four thousand, five hundred thirty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •