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12130000000000 = 2105101213
BaseRepresentation
bin1011000010000011110001…
…0101110101010000000000
31120221121122120000100102021
42300200330111311100000
53042214220000000000
641444240045131224
72361235464536611
oct260407425652000
946847576010367
1012130000000000
113957338853a33
12143aa60559b14
1369cb145943cc
142dd149087c08
151607e0c8411a
hexb083c575400

12130000000000 has 242 divisors, whose sum is σ = 30335180042798. Its totient is φ = 4848000000000.

The previous prime is 12129999999961. The next prime is 12130000000081. The reversal of 12130000000000 is 3121.

It can be written as a sum of positive squares in 11 ways, for example, as 3955707298816 + 8174292701184 = 1988896^2 + 2859072^2 .

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 21 ways as a sum of consecutive naturals, for example, 9999999394 + ... + 10000000606.

Almost surely, 212130000000000 is an apocalyptic number.

12130000000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12130000000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15167590021399).

12130000000000 is an abundant number, since it is smaller than the sum of its proper divisors (18205180042798).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12130000000000 is an frugal number, since it uses more digits than its factorization.

12130000000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1283 (or 1220 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 7.

Adding to 12130000000000 its reverse (3121), we get a palindrome (12130000003121).

The spelling of 12130000000000 in words is "twelve trillion, one hundred thirty billion", and thus it is an aban number.