Base | Representation |
---|---|
bin | 1011000010000011110010… |
… | …0101101000101111000010 |
3 | 1120221121122211210211121021 |
4 | 2300200330211220233002 |
5 | 3042214222030034132 |
6 | 41444240314020054 |
7 | 2361235545003502 |
oct | 260407445505702 |
9 | 46847584724537 |
10 | 12130004143042 |
11 | 3957340123735 |
12 | 143aa61a1762a |
13 | 69cb153b5106 |
14 | 2dd149845a02 |
15 | 1607e1301997 |
hex | b083c968bc2 |
12130004143042 has 16 divisors (see below), whose sum is σ = 18363089249280. Its totient is φ = 6009103639728.
The previous prime is 12130004143031. The next prime is 12130004143139. The reversal of 12130004143042 is 24034140003121.
It is a super-3 number, since 3×121300041430423 (a number of 40 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12130004142998 and 12130004143016.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 32123473 + ... + 32498884.
It is an arithmetic number, because the mean of its divisors is an integer number (1147693078080).
Almost surely, 212130004143042 is an apocalyptic number.
12130004143042 is a deficient number, since it is larger than the sum of its proper divisors (6233085106238).
12130004143042 is a wasteful number, since it uses less digits than its factorization.
12130004143042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 64623225.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 12130004143042 its reverse (24034140003121), we get a palindrome (36164144146163).
The spelling of 12130004143042 in words is "twelve trillion, one hundred thirty billion, four million, one hundred forty-three thousand, forty-two".
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