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12130004143042 = 212773964622357
BaseRepresentation
bin1011000010000011110010…
…0101101000101111000010
31120221121122211210211121021
42300200330211220233002
53042214222030034132
641444240314020054
72361235545003502
oct260407445505702
946847584724537
1012130004143042
113957340123735
12143aa61a1762a
1369cb153b5106
142dd149845a02
151607e1301997
hexb083c968bc2

12130004143042 has 16 divisors (see below), whose sum is σ = 18363089249280. Its totient is φ = 6009103639728.

The previous prime is 12130004143031. The next prime is 12130004143139. The reversal of 12130004143042 is 24034140003121.

It is a super-3 number, since 3×121300041430423 (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12130004142998 and 12130004143016.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 32123473 + ... + 32498884.

It is an arithmetic number, because the mean of its divisors is an integer number (1147693078080).

Almost surely, 212130004143042 is an apocalyptic number.

12130004143042 is a deficient number, since it is larger than the sum of its proper divisors (6233085106238).

12130004143042 is a wasteful number, since it uses less digits than its factorization.

12130004143042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 64623225.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 12130004143042 its reverse (24034140003121), we get a palindrome (36164144146163).

The spelling of 12130004143042 in words is "twelve trillion, one hundred thirty billion, four million, one hundred forty-three thousand, forty-two".

Divisors: 1 2 127 254 739 1478 93853 187706 64622357 129244714 8207039339 16414078678 47755921823 95511843646 6065002071521 12130004143042