Search a number
-
+
1213002017 is a prime number
BaseRepresentation
bin100100001001100…
…1111000100100001
310010112110212221122
41020103033010201
54441012031032
6320210502025
742026230013
oct11023170441
93115425848
101213002017
11572787407
1229a294915
131643c7596
14b71561b3
1571758012
hex484cf121

1213002017 has 2 divisors, whose sum is σ = 1213002018. Its totient is φ = 1213002016.

The previous prime is 1213001989. The next prime is 1213002029. The reversal of 1213002017 is 7102003121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 953018641 + 259983376 = 30871^2 + 16124^2 .

It is an emirp because it is prime and its reverse (7102003121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1213002017 - 26 = 1213001953 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1213001986 and 1213002004.

It is not a weakly prime, because it can be changed into another prime (1213004017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606501008 + 606501009.

It is an arithmetic number, because the mean of its divisors is an integer number (606501009).

Almost surely, 21213002017 is an apocalyptic number.

It is an amenable number.

1213002017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213002017 is an equidigital number, since it uses as much as digits as its factorization.

1213002017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 84, while the sum is 17.

The square root of 1213002017 is about 34828.1784909863. The cubic root of 1213002017 is about 1066.4827640745.

Adding to 1213002017 its reverse (7102003121), we get a palindrome (8315005138).

The spelling of 1213002017 in words is "one billion, two hundred thirteen million, two thousand, seventeen".