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1213002042103 = 4967244212209
BaseRepresentation
bin10001101001101100100…
…011100100101011110111
311021221222012100021200101
4101221230203210223313
5124333212010321403
62325125003254531
7153431215144225
oct21515443445367
94257865307611
101213002042103
11428482036835
12177107b1a447
138a502223047
14429d1265b15
15218463e271d
hex11a6c8e4af7

1213002042103 has 4 divisors (see below), whose sum is σ = 1213246259280. Its totient is φ = 1212757824928.

The previous prime is 1213002042071. The next prime is 1213002042167. The reversal of 1213002042103 is 3012402003121.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1213002042103 - 25 = 1213002042071 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1213002042403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 122101138 + ... + 122111071.

It is an arithmetic number, because the mean of its divisors is an integer number (303311564820).

Almost surely, 21213002042103 is an apocalyptic number.

1213002042103 is a deficient number, since it is larger than the sum of its proper divisors (244217177).

1213002042103 is an equidigital number, since it uses as much as digits as its factorization.

1213002042103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 244217176.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 1213002042103 its reverse (3012402003121), we get a palindrome (4225404045224).

The spelling of 1213002042103 in words is "one trillion, two hundred thirteen billion, two million, forty-two thousand, one hundred three".

Divisors: 1 4967 244212209 1213002042103