Base | Representation |
---|---|
bin | 10110100110000000… |
… | …10111010000101001 |
3 | 1011022100202222121102 |
4 | 23103000113100221 |
5 | 144320241204231 |
6 | 5323352251145 |
7 | 606410326625 |
oct | 132300272051 |
9 | 34270688542 |
10 | 12130022441 |
11 | 5165099439 |
12 | 24263a0ab5 |
13 | 11b408a594 |
14 | 830dc6185 |
15 | 4aeda5acb |
hex | 2d3017429 |
12130022441 has 2 divisors, whose sum is σ = 12130022442. Its totient is φ = 12130022440.
The previous prime is 12130022431. The next prime is 12130022449. The reversal of 12130022441 is 14422003121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6639805225 + 5490217216 = 81485^2 + 74096^2 .
It is an emirp because it is prime and its reverse (14422003121) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12130022441 is a prime.
It is not a weakly prime, because it can be changed into another prime (12130022449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6065011220 + 6065011221.
It is an arithmetic number, because the mean of its divisors is an integer number (6065011221).
Almost surely, 212130022441 is an apocalyptic number.
It is an amenable number.
12130022441 is a deficient number, since it is larger than the sum of its proper divisors (1).
12130022441 is an equidigital number, since it uses as much as digits as its factorization.
12130022441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 12130022441 its reverse (14422003121), we get a palindrome (26552025562).
The spelling of 12130022441 in words is "twelve billion, one hundred thirty million, twenty-two thousand, four hundred forty-one".
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