Base | Representation |
---|---|
bin | 11011100101001001110100… |
… | …000011010100110010111011 |
3 | 120220111012120101000111111212 |
4 | 123211021310003110302323 |
5 | 111344341221312333144 |
6 | 1105552350213113335 |
7 | 34356444215550215 |
oct | 3345116403246273 |
9 | 526435511014455 |
10 | 121300413402299 |
11 | 3571724208569a |
12 | 117309bb02884b |
13 | 528b770078a51 |
14 | 21d4d854ab5b5 |
15 | e0547e9da49e |
hex | 6e52740d4cbb |
121300413402299 has 2 divisors, whose sum is σ = 121300413402300. Its totient is φ = 121300413402298.
The previous prime is 121300413402241. The next prime is 121300413402323. The reversal of 121300413402299 is 992204314003121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121300413402299 - 232 = 121296118435003 is a prime.
It is not a weakly prime, because it can be changed into another prime (121300413402199) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60650206701149 + 60650206701150.
It is an arithmetic number, because the mean of its divisors is an integer number (60650206701150).
Almost surely, 2121300413402299 is an apocalyptic number.
121300413402299 is a deficient number, since it is larger than the sum of its proper divisors (1).
121300413402299 is an equidigital number, since it uses as much as digits as its factorization.
121300413402299 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 93312, while the sum is 41.
The spelling of 121300413402299 in words is "one hundred twenty-one trillion, three hundred billion, four hundred thirteen million, four hundred two thousand, two hundred ninety-nine".
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