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1213004134325 = 52405191197467
BaseRepresentation
bin10001101001101100101…
…011100011011110110101
311021221222100021120200002
4101221230223203132311
5124333213024244300
62325125120201045
7153431242010054
oct21515453433665
94257870246602
101213004134325
11428483235745
12177108769185
138a5027a6449
14429d164c39b
15218466a75d5
hex11a6cae37b5

1213004134325 has 12 divisors (see below), whose sum is σ = 1504163504160. Its totient is φ = 970378547760.

The previous prime is 1213004134319. The next prime is 1213004134357. The reversal of 1213004134325 is 5234314003121.

It is not a de Polignac number, because 1213004134325 - 212 = 1213004130229 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 414242 + ... + 1611708.

It is an arithmetic number, because the mean of its divisors is an integer number (125346958680).

Almost surely, 21213004134325 is an apocalyptic number.

It is an amenable number.

1213004134325 is a deficient number, since it is larger than the sum of its proper divisors (291159369835).

1213004134325 is a wasteful number, since it uses less digits than its factorization.

1213004134325 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1237996 (or 1237991 counting only the distinct ones).

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 1213004134325 its reverse (5234314003121), we get a palindrome (6447318137446).

The spelling of 1213004134325 in words is "one trillion, two hundred thirteen billion, four million, one hundred thirty-four thousand, three hundred twenty-five".

Divisors: 1 5 25 40519 202595 1012975 1197467 5987335 29936675 48520165373 242600826865 1213004134325