Base | Representation |
---|---|
bin | 1011000010000011111110… |
… | …0101100000101000111100 |
3 | 1120221121210100110021011022 |
4 | 2300200333211200220330 |
5 | 3042214322414112112 |
6 | 41444245312043312 |
7 | 2361240025353356 |
oct | 260407745405074 |
9 | 46847710407138 |
10 | 12130054441532 |
11 | 3957366558735 |
12 | 143aa76833538 |
13 | 69cb22946331 |
14 | 2dd1523ba0d6 |
15 | 1607e5939d72 |
hex | b083f960a3c |
12130054441532 has 6 divisors (see below), whose sum is σ = 21227595272688. Its totient is φ = 6065027220764.
The previous prime is 12130054441513. The next prime is 12130054441537. The reversal of 12130054441532 is 23514445003121.
It is a junction number, because it is equal to n+sod(n) for n = 12130054441492 and 12130054441501.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12130054441537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1516256805188 + ... + 1516256805195.
It is an arithmetic number, because the mean of its divisors is an integer number (3537932545448).
Almost surely, 212130054441532 is an apocalyptic number.
It is an amenable number.
12130054441532 is a deficient number, since it is larger than the sum of its proper divisors (9097540831156).
12130054441532 is a wasteful number, since it uses less digits than its factorization.
12130054441532 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3032513610387 (or 3032513610385 counting only the distinct ones).
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 12130054441532 its reverse (23514445003121), we get a palindrome (35644499444653).
The spelling of 12130054441532 in words is "twelve trillion, one hundred thirty billion, fifty-four million, four hundred forty-one thousand, five hundred thirty-two".
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