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12130153054115 = 52426030610823
BaseRepresentation
bin1011000010000100010101…
…1101101011111110100011
31120221122001020000022012012
42300201011131223332203
53042220023140212430
641444303153423135
72361242333506535
oct260410535537643
946848036008165
1012130153054115
113957407191838
12143aaa386aaab
1369cb3a1c2485
142dd161529855
151607ee418695
hexb084576bfa3

12130153054115 has 4 divisors (see below), whose sum is σ = 14556183664944. Its totient is φ = 9704122443288.

The previous prime is 12130153054067. The next prime is 12130153054127. The reversal of 12130153054115 is 51145035103121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12130153054115 - 230 = 12129079312291 is a prime.

It is a super-2 number, since 2×121301530541152 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1213015305407 + ... + 1213015305416.

It is an arithmetic number, because the mean of its divisors is an integer number (3639045916236).

Almost surely, 212130153054115 is an apocalyptic number.

12130153054115 is a deficient number, since it is larger than the sum of its proper divisors (2426030610829).

12130153054115 is an equidigital number, since it uses as much as digits as its factorization.

12130153054115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2426030610828.

The product of its (nonzero) digits is 9000, while the sum is 32.

Adding to 12130153054115 its reverse (51145035103121), we get a palindrome (63275188157236).

The spelling of 12130153054115 in words is "twelve trillion, one hundred thirty billion, one hundred fifty-three million, fifty-four thousand, one hundred fifteen".

Divisors: 1 5 2426030610823 12130153054115