Base | Representation |
---|---|
bin | 1011000010000100010101… |
… | …1101101011111101110011 |
3 | 1120221122001020000022010102 |
4 | 2300201011131223331303 |
5 | 3042220023140212232 |
6 | 41444303153423015 |
7 | 2361242333506436 |
oct | 260410535537563 |
9 | 46848036008112 |
10 | 12130153054067 |
11 | 39574071917a4 |
12 | 143aaa386aa6b |
13 | 69cb3a1c2449 |
14 | 2dd16152981d |
15 | 1607ee418662 |
hex | b084576bf73 |
12130153054067 has 2 divisors, whose sum is σ = 12130153054068. Its totient is φ = 12130153054066.
The previous prime is 12130153054057. The next prime is 12130153054127. The reversal of 12130153054067 is 76045035103121.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12130153054067 - 210 = 12130153053043 is a prime.
It is a super-2 number, since 2×121301530540672 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 12130153054067.
It is not a weakly prime, because it can be changed into another prime (12130153054057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6065076527033 + 6065076527034.
It is an arithmetic number, because the mean of its divisors is an integer number (6065076527034).
Almost surely, 212130153054067 is an apocalyptic number.
12130153054067 is a deficient number, since it is larger than the sum of its proper divisors (1).
12130153054067 is an equidigital number, since it uses as much as digits as its factorization.
12130153054067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 75600, while the sum is 38.
Adding to 12130153054067 its reverse (76045035103121), we get a palindrome (88175188157188).
The spelling of 12130153054067 in words is "twelve trillion, one hundred thirty billion, one hundred fifty-three million, fifty-four thousand, sixty-seven".
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