Base | Representation |
---|---|
bin | 1011000010000100100001… |
… | …0001111111100001111011 |
3 | 1120221122011111221122222002 |
4 | 2300201020101333201323 |
5 | 3042220122240220443 |
6 | 41444312002451215 |
7 | 2361243446326364 |
oct | 260411021774173 |
9 | 46848144848862 |
10 | 12130200320123 |
11 | 3957430935456 |
12 | 143aab7663b0b |
13 | 69cb46c31322 |
14 | 2dd167910b6b |
15 | 1608036532b8 |
hex | b084847f87b |
12130200320123 has 2 divisors, whose sum is σ = 12130200320124. Its totient is φ = 12130200320122.
The previous prime is 12130200320093. The next prime is 12130200320149. The reversal of 12130200320123 is 32102300203121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12130200320123 - 210 = 12130200319099 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12130200320095 and 12130200320104.
It is not a weakly prime, because it can be changed into another prime (12130200320153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6065100160061 + 6065100160062.
It is an arithmetic number, because the mean of its divisors is an integer number (6065100160062).
Almost surely, 212130200320123 is an apocalyptic number.
12130200320123 is a deficient number, since it is larger than the sum of its proper divisors (1).
12130200320123 is an equidigital number, since it uses as much as digits as its factorization.
12130200320123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 12130200320123 its reverse (32102300203121), we get a palindrome (44232500523244).
The spelling of 12130200320123 in words is "twelve trillion, one hundred thirty billion, two hundred million, three hundred twenty thousand, one hundred twenty-three".
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