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1213031201147 is a prime number
BaseRepresentation
bin10001101001101110010…
…010110011100101111011
311021222001020012201100222
4101221232102303211323
5124333241441414042
62325131524250255
7153432021041063
oct21515622634573
94258036181328
101213031201147
11428497542417
1217711584098b
138a50829230c
14429d50963a3
1521848c522d2
hex11a6e4b397b

1213031201147 has 2 divisors, whose sum is σ = 1213031201148. Its totient is φ = 1213031201146.

The previous prime is 1213031201099. The next prime is 1213031201191. The reversal of 1213031201147 is 7411021303121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1213031201147 - 210 = 1213031200123 is a prime.

It is a super-2 number, since 2×12130312011472 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1213031201647) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606515600573 + 606515600574.

It is an arithmetic number, because the mean of its divisors is an integer number (606515600574).

Almost surely, 21213031201147 is an apocalyptic number.

1213031201147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213031201147 is an equidigital number, since it uses as much as digits as its factorization.

1213031201147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 26.

Adding to 1213031201147 its reverse (7411021303121), we get a palindrome (8624052504268).

The spelling of 1213031201147 in words is "one trillion, two hundred thirteen billion, thirty-one million, two hundred one thousand, one hundred forty-seven".