Search a number
-
+
1213044024457 is a prime number
BaseRepresentation
bin10001101001101111000…
…011101110010010001001
311021222002010100012122101
4101221233003232102021
5124333303232240312
62325133103153401
7153432235036606
oct21515703562211
94258063305571
101213044024457
114284a38007a1
12177119ba5861
138a50ab31c85
14429d6a736ad
1521849e36a57
hex11a6f0ee489

1213044024457 has 2 divisors, whose sum is σ = 1213044024458. Its totient is φ = 1213044024456.

The previous prime is 1213044024427. The next prime is 1213044024473. The reversal of 1213044024457 is 7544204403121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 875757200761 + 337286823696 = 935819^2 + 580764^2 .

It is an emirp because it is prime and its reverse (7544204403121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1213044024457 - 27 = 1213044024329 is a prime.

It is not a weakly prime, because it can be changed into another prime (1213044024427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606522012228 + 606522012229.

It is an arithmetic number, because the mean of its divisors is an integer number (606522012229).

Almost surely, 21213044024457 is an apocalyptic number.

It is an amenable number.

1213044024457 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213044024457 is an equidigital number, since it uses as much as digits as its factorization.

1213044024457 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 107520, while the sum is 37.

Adding to 1213044024457 its reverse (7544204403121), we get a palindrome (8757248427578).

The spelling of 1213044024457 in words is "one trillion, two hundred thirteen billion, forty-four million, twenty-four thousand, four hundred fifty-seven".