12130441121 has 2 divisors, whose sum is σ = 12130441122. Its totient is φ = 12130441120.

The previous prime is 12130441087. The next prime is 12130441129. The reversal of 12130441121 is 12114403121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11860299025 + 270142096 = 108905^2 + 16436^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12130441121 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12130441093 and 12130441102.

It is not a weakly prime, because it can be changed into another prime (12130441129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6065220560 + 6065220561.

It is an arithmetic number, because the mean of its divisors is an integer number (6065220561).

Almost surely, 2^12130441121 is an apocalyptic number.

It is an amenable number.

12130441121 is a deficient number, since it is larger than the sum of its proper divisors (1).

12130441121 is an equidigital number, since it uses as much as digits as its factorization.

12130441121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 12130441121 its reverse (12114403121), we get a palindrome (24244844242).

The spelling of 12130441121 in words is "twelve billion, one hundred thirty million, four hundred forty-one thousand, one hundred twenty-one".