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121304646433121 is a prime number
BaseRepresentation
bin11011100101001101110000…
…010111000011100101100001
3120220111121111101012202011012
4123211031300113003211201
5111344423403441324441
61105554330225430305
734356654135662024
oct3345156027034541
9526447441182135
10121304646433121
1135719014562378
12117317a079b395
13528bc9604b108
1421d52677611bb
15e0562b4419eb
hex6e53705c3961

121304646433121 has 2 divisors, whose sum is σ = 121304646433122. Its totient is φ = 121304646433120.

The previous prime is 121304646433099. The next prime is 121304646433129. The reversal of 121304646433121 is 121334646403121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 107575479859600 + 13729166573521 = 10371860^2 + 3705289^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121304646433121 is a prime.

It is not a weakly prime, because it can be changed into another prime (121304646433129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60652323216560 + 60652323216561.

It is an arithmetic number, because the mean of its divisors is an integer number (60652323216561).

Almost surely, 2121304646433121 is an apocalyptic number.

It is an amenable number.

121304646433121 is a deficient number, since it is larger than the sum of its proper divisors (1).

121304646433121 is an equidigital number, since it uses as much as digits as its factorization.

121304646433121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 248832, while the sum is 41.

The spelling of 121304646433121 in words is "one hundred twenty-one trillion, three hundred four billion, six hundred forty-six million, four hundred thirty-three thousand, one hundred twenty-one".