Base | Representation |
---|---|
bin | 1011000010000111100000… |
… | …0101101110010000011011 |
3 | 1120221201020102020001102222 |
4 | 2300201320011232100123 |
5 | 3042223243104110021 |
6 | 41444523334214255 |
7 | 2361302356066022 |
oct | 260417005562033 |
9 | 46851212201388 |
10 | 12131002410011 |
11 | 3957802673461 |
12 | 143b0a01b438b |
13 | 69cc44166524 |
14 | 2dd2022618b9 |
15 | 16084dc8e6ab |
hex | b087816e41b |
12131002410011 has 2 divisors, whose sum is σ = 12131002410012. Its totient is φ = 12131002410010.
The previous prime is 12131002409959. The next prime is 12131002410041. The reversal of 12131002410011 is 11001420013121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12131002410011 is a prime.
It is a super-2 number, since 2×121310024100112 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12131002410041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6065501205005 + 6065501205006.
It is an arithmetic number, because the mean of its divisors is an integer number (6065501205006).
Almost surely, 212131002410011 is an apocalyptic number.
12131002410011 is a deficient number, since it is larger than the sum of its proper divisors (1).
12131002410011 is an equidigital number, since it uses as much as digits as its factorization.
12131002410011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 12131002410011 its reverse (11001420013121), we get a palindrome (23132422423132).
The spelling of 12131002410011 in words is "twelve trillion, one hundred thirty-one billion, two million, four hundred ten thousand, eleven".
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