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1213110011011 is a prime number
BaseRepresentation
bin10001101001110010111…
…111011100010010000011
311021222020201111200011211
4101221302333130102003
5124333422130323021
62325143421350551
7153433665646333
oct21516277342203
94258221450154
101213110011011
11428527a80438
12177138108457
138a51b6c6a82
1442a0172d0c3
1521850b1d3e1
hex11a72fdc483

1213110011011 has 2 divisors, whose sum is σ = 1213110011012. Its totient is φ = 1213110011010.

The previous prime is 1213110010997. The next prime is 1213110011017. The reversal of 1213110011011 is 1101100113121.

It is a strong prime.

It is an emirp because it is prime and its reverse (1101100113121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1213110011011 - 27 = 1213110010883 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1213110010982 and 1213110011000.

It is not a weakly prime, because it can be changed into another prime (1213110011017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606555005505 + 606555005506.

It is an arithmetic number, because the mean of its divisors is an integer number (606555005506).

Almost surely, 21213110011011 is an apocalyptic number.

1213110011011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213110011011 is an equidigital number, since it uses as much as digits as its factorization.

1213110011011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 1213110011011 its reverse (1101100113121), we get a palindrome (2314210124132).

The spelling of 1213110011011 in words is "one trillion, two hundred thirteen billion, one hundred ten million, eleven thousand, eleven".