Base | Representation |
---|---|
bin | 1011000010000111111000… |
… | …0110001111101000001111 |
3 | 1120221201111102220020000212 |
4 | 2300201332012033220033 |
5 | 3042223444410204444 |
6 | 41444541334513035 |
7 | 2361305021632364 |
oct | 260417606175017 |
9 | 46851442806025 |
10 | 12131103209999 |
11 | 3957854560a34 |
12 | 143b109b0577b |
13 | 69cc5bcca1a7 |
14 | 2dd2117c046b |
15 | 160857a5119e |
hex | b087e18fa0f |
12131103209999 has 4 divisors (see below), whose sum is σ = 12284661478560. Its totient is φ = 11977544941440.
The previous prime is 12131103209989. The next prime is 12131103210001. The reversal of 12131103209999 is 99990230113121.
12131103209999 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12131103209999 - 224 = 12131086432783 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12131103209989) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 76779134162 + ... + 76779134319.
It is an arithmetic number, because the mean of its divisors is an integer number (3071165369640).
Almost surely, 212131103209999 is an apocalyptic number.
12131103209999 is a deficient number, since it is larger than the sum of its proper divisors (153558268561).
12131103209999 is an equidigital number, since it uses as much as digits as its factorization.
12131103209999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 153558268560.
The product of its (nonzero) digits is 236196, while the sum is 50.
The spelling of 12131103209999 in words is "twelve trillion, one hundred thirty-one billion, one hundred three million, two hundred nine thousand, nine hundred ninety-nine".
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