Base | Representation |
---|---|
bin | 1011000010000111111000… |
… | …0110001111101000000101 |
3 | 1120221201111102220020000111 |
4 | 2300201332012033220011 |
5 | 3042223444410204424 |
6 | 41444541334513021 |
7 | 2361305021632351 |
oct | 260417606175005 |
9 | 46851442806014 |
10 | 12131103209989 |
11 | 3957854560a25 |
12 | 143b109b05771 |
13 | 69cc5bcca19a |
14 | 2dd2117c0461 |
15 | 160857a51194 |
hex | b087e18fa05 |
12131103209989 has 2 divisors, whose sum is σ = 12131103209990. Its totient is φ = 12131103209988.
The previous prime is 12131103209941. The next prime is 12131103210001. The reversal of 12131103209989 is 98990230113121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8705698093764 + 3425405116225 = 2950542^2 + 1850785^2 .
It is a cyclic number.
It is not a de Polignac number, because 12131103209989 - 211 = 12131103207941 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12131103207989) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6065551604994 + 6065551604995.
It is an arithmetic number, because the mean of its divisors is an integer number (6065551604995).
Almost surely, 212131103209989 is an apocalyptic number.
It is an amenable number.
12131103209989 is a deficient number, since it is larger than the sum of its proper divisors (1).
12131103209989 is an equidigital number, since it uses as much as digits as its factorization.
12131103209989 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 209952, while the sum is 49.
The spelling of 12131103209989 in words is "twelve trillion, one hundred thirty-one billion, one hundred three million, two hundred nine thousand, nine hundred eighty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •