Base | Representation |
---|---|
bin | 11011100101010011111101… |
… | …100110011100000000000000 |
3 | 120220112020200211210211200110 |
4 | 123211103331212130000000 |
5 | 111400031031110120112 |
6 | 1110001351422551320 |
7 | 34360311243016410 |
oct | 3345237546340000 |
9 | 526466624724613 |
10 | 121311311020032 |
11 | 35720924545141 |
12 | 11732b40738540 |
13 | 528c7b8a07473 |
14 | 21d56da92a640 |
15 | e058bb5a413c |
hex | 6e54fd99c000 |
121311311020032 has 240 divisors, whose sum is σ = 369742333087232. Its totient is φ = 34656347750400.
The previous prime is 121311311020019. The next prime is 121311311020037. The reversal of 121311311020032 is 230020113113121.
121311311020032 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a junction number, because it is equal to n+sod(n) for n = 121311311019990 and 121311311020008.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121311311020037) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4232316933 + ... + 4232345595.
Almost surely, 2121311311020032 is an apocalyptic number.
121311311020032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 121311311020032, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (184871166543616).
121311311020032 is an abundant number, since it is smaller than the sum of its proper divisors (248431022067200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121311311020032 is an equidigital number, since it uses as much as digits as its factorization.
121311311020032 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 41002 (or 40976 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 121311311020032 its reverse (230020113113121), we get a palindrome (351331424133153).
The spelling of 121311311020032 in words is "one hundred twenty-one trillion, three hundred eleven billion, three hundred eleven million, twenty thousand, thirty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •