Base | Representation |
---|---|
bin | 111000011111011000… |
… | …1000110110000100001 |
3 | 102121010110012110020211 |
4 | 1300332301012300201 |
5 | 3441421402110132 |
6 | 131421404134121 |
7 | 11523141133222 |
oct | 1607661066041 |
9 | 377113173224 |
10 | 121312144417 |
11 | 474a25a76a2 |
12 | 1b617237341 |
13 | b593cb4c99 |
14 | 5c2b709249 |
15 | 3250294147 |
hex | 1c3ec46c21 |
121312144417 has 2 divisors, whose sum is σ = 121312144418. Its totient is φ = 121312144416.
The previous prime is 121312144361. The next prime is 121312144453. The reversal of 121312144417 is 714441213121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 118192251681 + 3119892736 = 343791^2 + 55856^2 .
It is a cyclic number.
It is not a de Polignac number, because 121312144417 - 215 = 121312111649 is a prime.
It is not a weakly prime, because it can be changed into another prime (121312144487) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60656072208 + 60656072209.
It is an arithmetic number, because the mean of its divisors is an integer number (60656072209).
Almost surely, 2121312144417 is an apocalyptic number.
It is an amenable number.
121312144417 is a deficient number, since it is larger than the sum of its proper divisors (1).
121312144417 is an equidigital number, since it uses as much as digits as its factorization.
121312144417 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5376, while the sum is 31.
Adding to 121312144417 its reverse (714441213121), we get a palindrome (835753357538).
The spelling of 121312144417 in words is "one hundred twenty-one billion, three hundred twelve million, one hundred forty-four thousand, four hundred seventeen".
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