1213124534141 has 4 divisors (see below), whose sum is σ = 1306441806012. Its totient is φ = 1119807262272.

The previous prime is 1213124534117. The next prime is 1213124534161. The reversal of 1213124534141 is 1414354213121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 540033916900 + 673090617241 = 734870^2 + 820421^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1213124534141 is a prime.

It is a super-2 number, since 2×1213124534141² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1213124534098 and 1213124534107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1213124534161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46658635916 + ... + 46658635941.

It is an arithmetic number, because the mean of its divisors is an integer number (326610451503).

Almost surely, 2^{1213124534141} is an apocalyptic number.

It is an amenable number.

1213124534141 is a deficient number, since it is larger than the sum of its proper divisors (93317271871).

1213124534141 is an equidigital number, since it uses as much as digits as its factorization.

1213124534141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 93317271870.

The product of its digits is 11520, while the sum is 32.

Adding to 1213124534141 its reverse (1414354213121), we get a palindrome (2627478747262).

The spelling of 1213124534141 in words is "one trillion, two hundred thirteen billion, one hundred twenty-four million, five hundred thirty-four thousand, one hundred forty-one".