Base | Representation |
---|---|
bin | 10110100110001010… |
… | …01111110000001011 |
3 | 1011022110012000101201 |
4 | 23103011033300023 |
5 | 144321103134121 |
6 | 5323435525031 |
7 | 606424240414 |
oct | 132305176013 |
9 | 34273160351 |
10 | 12131302411 |
11 | 5165893068 |
12 | 24268b9777 |
13 | 11b4418067 |
14 | 83123a80b |
15 | 4b0059e91 |
hex | 2d314fc0b |
12131302411 has 2 divisors, whose sum is σ = 12131302412. Its totient is φ = 12131302410.
The previous prime is 12131302387. The next prime is 12131302439. The reversal of 12131302411 is 11420313121.
12131302411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12131302411 - 29 = 12131301899 is a prime.
It is not a weakly prime, because it can be changed into another prime (12131302111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6065651205 + 6065651206.
It is an arithmetic number, because the mean of its divisors is an integer number (6065651206).
Almost surely, 212131302411 is an apocalyptic number.
12131302411 is a deficient number, since it is larger than the sum of its proper divisors (1).
12131302411 is an equidigital number, since it uses as much as digits as its factorization.
12131302411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 12131302411 its reverse (11420313121), we get a palindrome (23551615532).
The spelling of 12131302411 in words is "twelve billion, one hundred thirty-one million, three hundred two thousand, four hundred eleven".
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