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12131303334442 = 26065651667221
BaseRepresentation
bin1011000010001000101000…
…0001101010001000101010
31120221202000101110121011021
42300202022001222020222
53042224402123200232
641445013244123054
72361313001645515
oct260421201521052
946852011417137
1012131303334442
113957947519436
12143b164b3648a
1369cc915c9016
142dd2301d5d7c
1516086a3d2397
hexb088a06a22a

12131303334442 has 4 divisors (see below), whose sum is σ = 18196955001666. Its totient is φ = 6065651667220.

The previous prime is 12131303334433. The next prime is 12131303334487. The reversal of 12131303334442 is 24443330313121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 11770656243921 + 360647090521 = 3430839^2 + 600539^2 .

It is a junction number, because it is equal to n+sod(n) for n = 12131303334398 and 12131303334407.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3032825833609 + ... + 3032825833612.

Almost surely, 212131303334442 is an apocalyptic number.

12131303334442 is a deficient number, since it is larger than the sum of its proper divisors (6065651667224).

12131303334442 is an equidigital number, since it uses as much as digits as its factorization.

12131303334442 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6065651667223.

The product of its (nonzero) digits is 62208, while the sum is 34.

Adding to 12131303334442 its reverse (24443330313121), we get a palindrome (36574633647563).

The spelling of 12131303334442 in words is "twelve trillion, one hundred thirty-one billion, three hundred three million, three hundred thirty-four thousand, four hundred forty-two".

Divisors: 1 2 6065651667221 12131303334442