Search a number
-
+
121320110211132 = 223723337259371861
BaseRepresentation
bin11011100101011100001010…
…000100101100000000111100
3120220120002102002001001200010
4123211130022010230000330
5111400202041203224012
61110005404512103220
734361042266633650
oct3345341204540074
9526502362031603
10121320110211132
113572462a4506a8
1211734797534b10
13529058b9a9211
1421d5cd33cca60
15e05c33d16c3c
hex6e570a12c03c

121320110211132 has 192 divisors, whose sum is σ = 338723424958464. Its totient is φ = 33044212776960.

The previous prime is 121320110211049. The next prime is 121320110211239. The reversal of 121320110211132 is 231112011023121.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a junction number, because it is equal to n+sod(n) for n = 121320110211099 and 121320110211108.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1688224882 + ... + 1688296742.

It is an arithmetic number, because the mean of its divisors is an integer number (1764184504992).

Almost surely, 2121320110211132 is an apocalyptic number.

121320110211132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 121320110211132, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (169361712479232).

121320110211132 is an abundant number, since it is smaller than the sum of its proper divisors (217403314747332).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121320110211132 is a wasteful number, since it uses less digits than its factorization.

121320110211132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 74828 (or 74826 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 21.

Adding to 121320110211132 its reverse (231112011023121), we get a palindrome (352432121234253).

The spelling of 121320110211132 in words is "one hundred twenty-one trillion, three hundred twenty billion, one hundred ten million, two hundred eleven thousand, one hundred thirty-two".