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1213203232147 is a prime number
BaseRepresentation
bin10001101001111000100…
…011000011010110010011
311021222111012220210112111
4101221320203003112103
5124334120011412042
62325200551410151
7153436210216144
oct21517043032623
94258435823474
101213203232147
114285756618a5
12177163383957
138a534b05bca
1442a0dc77acb
1521858dd4517
hex11a788c3593

1213203232147 has 2 divisors, whose sum is σ = 1213203232148. Its totient is φ = 1213203232146.

The previous prime is 1213203232133. The next prime is 1213203232159. The reversal of 1213203232147 is 7412323023121.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1213203232147 is a prime.

It is not a weakly prime, because it can be changed into another prime (1213203232447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606601616073 + 606601616074.

It is an arithmetic number, because the mean of its divisors is an integer number (606601616074).

Almost surely, 21213203232147 is an apocalyptic number.

1213203232147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213203232147 is an equidigital number, since it uses as much as digits as its factorization.

1213203232147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12096, while the sum is 31.

Adding to 1213203232147 its reverse (7412323023121), we get a palindrome (8625526255268).

The spelling of 1213203232147 in words is "one trillion, two hundred thirteen billion, two hundred three million, two hundred thirty-two thousand, one hundred forty-seven".