Base | Representation |
---|---|
bin | 10001101001111000100… |
… | …011000011010110010011 |
3 | 11021222111012220210112111 |
4 | 101221320203003112103 |
5 | 124334120011412042 |
6 | 2325200551410151 |
7 | 153436210216144 |
oct | 21517043032623 |
9 | 4258435823474 |
10 | 1213203232147 |
11 | 4285756618a5 |
12 | 177163383957 |
13 | 8a534b05bca |
14 | 42a0dc77acb |
15 | 21858dd4517 |
hex | 11a788c3593 |
1213203232147 has 2 divisors, whose sum is σ = 1213203232148. Its totient is φ = 1213203232146.
The previous prime is 1213203232133. The next prime is 1213203232159. The reversal of 1213203232147 is 7412323023121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1213203232147 is a prime.
It is not a weakly prime, because it can be changed into another prime (1213203232447) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606601616073 + 606601616074.
It is an arithmetic number, because the mean of its divisors is an integer number (606601616074).
Almost surely, 21213203232147 is an apocalyptic number.
1213203232147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1213203232147 is an equidigital number, since it uses as much as digits as its factorization.
1213203232147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 31.
Adding to 1213203232147 its reverse (7412323023121), we get a palindrome (8625526255268).
The spelling of 1213203232147 in words is "one trillion, two hundred thirteen billion, two hundred three million, two hundred thirty-two thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •